3.551 \(\int \frac{1}{(d+e x^2)^{5/2} (a+b \cosh ^{-1}(c x))^2} \, dx\)

Optimal. Leaf size=24 \[ \text{Unintegrable}\left (\frac{1}{\left (d+e x^2\right )^{5/2} \left (a+b \cosh ^{-1}(c x)\right )^2},x\right ) \]

[Out]

Unintegrable[1/((d + e*x^2)^(5/2)*(a + b*ArcCosh[c*x])^2), x]

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Rubi [A]  time = 0.0503068, antiderivative size = 0, normalized size of antiderivative = 0., number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0., Rules used = {} \[ \int \frac{1}{\left (d+e x^2\right )^{5/2} \left (a+b \cosh ^{-1}(c x)\right )^2} \, dx \]

Verification is Not applicable to the result.

[In]

Int[1/((d + e*x^2)^(5/2)*(a + b*ArcCosh[c*x])^2),x]

[Out]

Defer[Int][1/((d + e*x^2)^(5/2)*(a + b*ArcCosh[c*x])^2), x]

Rubi steps

\begin{align*} \int \frac{1}{\left (d+e x^2\right )^{5/2} \left (a+b \cosh ^{-1}(c x)\right )^2} \, dx &=\int \frac{1}{\left (d+e x^2\right )^{5/2} \left (a+b \cosh ^{-1}(c x)\right )^2} \, dx\\ \end{align*}

Mathematica [F]  time = 180.004, size = 0, normalized size = 0. \[ \text{\$Aborted} \]

Verification is Not applicable to the result.

[In]

Integrate[1/((d + e*x^2)^(5/2)*(a + b*ArcCosh[c*x])^2),x]

[Out]

$Aborted

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Maple [A]  time = 0.219, size = 0, normalized size = 0. \begin{align*} \int{\frac{1}{ \left ( a+b{\rm arccosh} \left (cx\right ) \right ) ^{2}} \left ( e{x}^{2}+d \right ) ^{-{\frac{5}{2}}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(e*x^2+d)^(5/2)/(a+b*arccosh(c*x))^2,x)

[Out]

int(1/(e*x^2+d)^(5/2)/(a+b*arccosh(c*x))^2,x)

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Maxima [A]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x^2+d)^(5/2)/(a+b*arccosh(c*x))^2,x, algorithm="maxima")

[Out]

-(c^3*x^3 + (c^2*x^2 - 1)*sqrt(c*x + 1)*sqrt(c*x - 1) - c*x)/((b^2*c^3*e^2*x^6 + (2*c^3*d*e - c*e^2)*b^2*x^4 -
b^2*c*d^2 + (c^3*d^2 - 2*c*d*e)*b^2*x^2 + (b^2*c^2*e^2*x^5 + 2*b^2*c^2*d*e*x^3 + b^2*c^2*d^2*x)*sqrt(c*x + 1)
*sqrt(c*x - 1))*sqrt(e*x^2 + d)*log(c*x + sqrt(c*x + 1)*sqrt(c*x - 1)) + (a*b*c^3*e^2*x^6 + (2*c^3*d*e - c*e^2
)*a*b*x^4 - a*b*c*d^2 + (c^3*d^2 - 2*c*d*e)*a*b*x^2 + (a*b*c^2*e^2*x^5 + 2*a*b*c^2*d*e*x^3 + a*b*c^2*d^2*x)*sq
rt(c*x + 1)*sqrt(c*x - 1))*sqrt(e*x^2 + d)) - integrate((4*c^5*e*x^6 - (c^5*d + 8*c^3*e)*x^4 + (4*c^3*e*x^4 -
(c^3*d + 6*c*e)*x^2 - c*d)*(c*x + 1)*(c*x - 1) + 2*(c^3*d + 2*c*e)*x^2 + (8*c^4*e*x^5 - 2*(c^4*d + 7*c^2*e)*x^
3 + (c^2*d + 5*e)*x)*sqrt(c*x + 1)*sqrt(c*x - 1) - c*d)/((b^2*c^5*e^3*x^10 + (3*c^5*d*e^2 - 2*c^3*e^3)*b^2*x^8
+ (3*c^5*d^2*e - 6*c^3*d*e^2 + c*e^3)*b^2*x^6 + (c^5*d^3 - 6*c^3*d^2*e + 3*c*d*e^2)*b^2*x^4 + b^2*c*d^3 - (2*
c^3*d^3 - 3*c*d^2*e)*b^2*x^2 + (b^2*c^3*e^3*x^8 + 3*b^2*c^3*d*e^2*x^6 + 3*b^2*c^3*d^2*e*x^4 + b^2*c^3*d^3*x^2)
*(c*x + 1)*(c*x - 1) + 2*(b^2*c^4*e^3*x^9 + (3*c^4*d*e^2 - c^2*e^3)*b^2*x^7 - b^2*c^2*d^3*x + 3*(c^4*d^2*e - c
^2*d*e^2)*b^2*x^5 + (c^4*d^3 - 3*c^2*d^2*e)*b^2*x^3)*sqrt(c*x + 1)*sqrt(c*x - 1))*sqrt(e*x^2 + d)*log(c*x + sq
rt(c*x + 1)*sqrt(c*x - 1)) + (a*b*c^5*e^3*x^10 + (3*c^5*d*e^2 - 2*c^3*e^3)*a*b*x^8 + (3*c^5*d^2*e - 6*c^3*d*e^
2 + c*e^3)*a*b*x^6 + (c^5*d^3 - 6*c^3*d^2*e + 3*c*d*e^2)*a*b*x^4 + a*b*c*d^3 - (2*c^3*d^3 - 3*c*d^2*e)*a*b*x^2
+ (a*b*c^3*e^3*x^8 + 3*a*b*c^3*d*e^2*x^6 + 3*a*b*c^3*d^2*e*x^4 + a*b*c^3*d^3*x^2)*(c*x + 1)*(c*x - 1) + 2*(a*
b*c^4*e^3*x^9 + (3*c^4*d*e^2 - c^2*e^3)*a*b*x^7 - a*b*c^2*d^3*x + 3*(c^4*d^2*e - c^2*d*e^2)*a*b*x^5 + (c^4*d^3
- 3*c^2*d^2*e)*a*b*x^3)*sqrt(c*x + 1)*sqrt(c*x - 1))*sqrt(e*x^2 + d)), x)

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Fricas [A]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{e x^{2} + d}}{a^{2} e^{3} x^{6} + 3 \, a^{2} d e^{2} x^{4} + 3 \, a^{2} d^{2} e x^{2} + a^{2} d^{3} +{\left (b^{2} e^{3} x^{6} + 3 \, b^{2} d e^{2} x^{4} + 3 \, b^{2} d^{2} e x^{2} + b^{2} d^{3}\right )} \operatorname{arcosh}\left (c x\right )^{2} + 2 \,{\left (a b e^{3} x^{6} + 3 \, a b d e^{2} x^{4} + 3 \, a b d^{2} e x^{2} + a b d^{3}\right )} \operatorname{arcosh}\left (c x\right )}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x^2+d)^(5/2)/(a+b*arccosh(c*x))^2,x, algorithm="fricas")

[Out]

integral(sqrt(e*x^2 + d)/(a^2*e^3*x^6 + 3*a^2*d*e^2*x^4 + 3*a^2*d^2*e*x^2 + a^2*d^3 + (b^2*e^3*x^6 + 3*b^2*d*e
^2*x^4 + 3*b^2*d^2*e*x^2 + b^2*d^3)*arccosh(c*x)^2 + 2*(a*b*e^3*x^6 + 3*a*b*d*e^2*x^4 + 3*a*b*d^2*e*x^2 + a*b*
d^3)*arccosh(c*x)), x)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x**2+d)**(5/2)/(a+b*acosh(c*x))**2,x)

[Out]

Timed out

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Giac [A]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (e x^{2} + d\right )}^{\frac{5}{2}}{\left (b \operatorname{arcosh}\left (c x\right ) + a\right )}^{2}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x^2+d)^(5/2)/(a+b*arccosh(c*x))^2,x, algorithm="giac")

[Out]

integrate(1/((e*x^2 + d)^(5/2)*(b*arccosh(c*x) + a)^2), x)